12=(b/6)=16

Solution for 12=(b/6)=16 equation:

12=(b/6)=16

We move all terms to the left:

12-((b/6))=0

We add all the numbers together, and all the variables

-((+b/6))+12=0

We multiply all the terms by the denominator


-((+b+12*6))=0


We calculate terms in parentheses: -((+b+12*6)), so:

(+b+12*6)

We add all the numbers together, and all the variables

(b+72)

We get rid of parentheses

b+72

Back to the equation:

-(b+72)


We get rid of parentheses

-b-72=0

We add all the numbers together, and all the variables

-1b-72=0

We move all terms containing b to the left, all other terms to the right

-b=72

b=72/-1

b=-72