12=(x/(40+2x))

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Solution for 12=(x/(40+2x)) equation: 



12=(x/(40+2x))

We move all terms to the left:

12-((x/(40+2x)))=0



Domain of the equation: (40+2x)))!=0

We move all terms containing x to the left, all other terms to the right

2x))!=-40

x!=-40/1

x!=-40

x∈R



We add all the numbers together, and all the variables

-((x/(2x+40)))+12=0

We multiply all the terms by the denominator


-((x+12*(2x+40)))=0



We calculate terms in parentheses: -((x+12*(2x+40))), so:

(x+12*(2x+40))



We calculate terms in parentheses: +(x+12*(2x+40)), so:

x+12*(2x+40)

We multiply parentheses

x+24x+480

We add all the numbers together, and all the variables

25x+480

Back to the equation:

+(25x+480)



We get rid of parentheses

25x+480

Back to the equation:

-(25x+480)



We get rid of parentheses

-25x-480=0

We move all terms containing x to the left, all other terms to the right

-25x=480

x=480/-25

x=-19+1/5

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