12=(z/30)-(-10)

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Solution for 12=(z/30)-(-10) equation: 



12=(z/30)-(-10)

We move all terms to the left:

12-((z/30)-(-10))=0

We add all the numbers together, and all the variables

-((+z/30)-(-10))+12=0

We multiply all the terms by the denominator


-((+z+12*30)-(-10))=0



We calculate terms in parentheses: -((+z+12*30)-(-10)), so:

(+z+12*30)-(-10)

We add all the numbers together, and all the variables

(z+360)-(-10)

We add all the numbers together, and all the variables

(z+360)+10

We get rid of parentheses

z+360+10

We add all the numbers together, and all the variables

z+370

Back to the equation:

-(z+370)



We get rid of parentheses

-z-370=0

We add all the numbers together, and all the variables

-1z-370=0

We move all terms containing z to the left, all other terms to the right

-z=370

z=370/-1

z=-370

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