12=-(2+c)-(4+2c)

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Solution for 12=-(2+c)-(4+2c) equation:


Simplifying
12 = -1(2 + c) + -1(4 + 2c)
12 = (2 * -1 + c * -1) + -1(4 + 2c)
12 = (-2 + -1c) + -1(4 + 2c)
12 = -2 + -1c + (4 * -1 + 2c * -1)
12 = -2 + -1c + (-4 + -2c)

Reorder the terms:
12 = -2 + -4 + -1c + -2c

Combine like terms: -2 + -4 = -6
12 = -6 + -1c + -2c

Combine like terms: -1c + -2c = -3c
12 = -6 + -3c

Solving
12 = -6 + -3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '3c' to each side of the equation.
12 + 3c = -6 + -3c + 3c

Combine like terms: -3c + 3c = 0
12 + 3c = -6 + 0
12 + 3c = -6

Add '-12' to each side of the equation.
12 + -12 + 3c = -6 + -12

Combine like terms: 12 + -12 = 0
0 + 3c = -6 + -12
3c = -6 + -12

Combine like terms: -6 + -12 = -18
3c = -18

Divide each side by '3'.
c = -6

Simplifying
c = -6

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