12=-16t2+24t+3

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Solution for 12=-16t2+24t+3 equation: 



12=-16t^2+24t+3

We move all terms to the left:

12-(-16t^2+24t+3)=0

We get rid of parentheses

16t^2-24t-3+12=0

We add all the numbers together, and all the variables

16t^2-24t+9=0

a = 16; b = -24; c = +9;
Δ = b2-4ac
Δ = -242-4·16·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{24}{32}=3/4$

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