12=-3(z-20)

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Solution for 12=-3(z-20) equation: 



12=-3(z-20)

We move all terms to the left:

12-(-3(z-20))=0



We calculate terms in parentheses: -(-3(z-20)), so:

-3(z-20)

We multiply parentheses

-3z+60

Back to the equation:

-(-3z+60)



We get rid of parentheses

3z-60+12=0

We add all the numbers together, and all the variables

3z-48=0

We move all terms containing z to the left, all other terms to the right

3z=48

z=48/3

z=16

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