12=-4(-6x-3)x=

Solution for 12=-4(-6x-3)x= equation:

12=-4(-6x-3)x=

We move all terms to the left:

12-(-4(-6x-3)x)=0


We calculate terms in parentheses: -(-4(-6x-3)x), so:

-4(-6x-3)x

We multiply parentheses

24x^2+12x

Back to the equation:

-(24x^2+12x)


We get rid of parentheses

-24x^2-12x+12=0

a = -24; b = -12; c = +12;
Δ = b2-4ac
Δ = -122-4·(-24)·12
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-36}{2*-24}=\frac{-24}{-48}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+36}{2*-24}=\frac{48}{-48}
=-1
$