12=-4(3x-2)+x-7

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Solution for 12=-4(3x-2)+x-7 equation: 



12=-4(3x-2)+x-7

We move all terms to the left:

12-(-4(3x-2)+x-7)=0



We calculate terms in parentheses: -(-4(3x-2)+x-7), so:

-4(3x-2)+x-7

We add all the numbers together, and all the variables

x-4(3x-2)-7

We multiply parentheses

x-12x+8-7

We add all the numbers together, and all the variables

-11x+1

Back to the equation:

-(-11x+1)



We get rid of parentheses

11x-1+12=0

We add all the numbers together, and all the variables

11x+11=0

We move all terms containing x to the left, all other terms to the right

11x=-11

x=-11/11

x=-1

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