12=-6(z-7)

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Solution for 12=-6(z-7) equation: 



12=-6(z-7)

We move all terms to the left:

12-(-6(z-7))=0



We calculate terms in parentheses: -(-6(z-7)), so:

-6(z-7)

We multiply parentheses

-6z+42

Back to the equation:

-(-6z+42)



We get rid of parentheses

6z-42+12=0

We add all the numbers together, and all the variables

6z-30=0

We move all terms containing z to the left, all other terms to the right

6z=30

z=30/6

z=5

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