12=-6v+2(v-2)

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Solution for 12=-6v+2(v-2) equation:



12=-6v+2(v-2)
We move all terms to the left:
12-(-6v+2(v-2))=0
We calculate terms in parentheses: -(-6v+2(v-2)), so:
-6v+2(v-2)
We multiply parentheses
-6v+2v-4
We add all the numbers together, and all the variables
-4v-4
Back to the equation:
-(-4v-4)
We get rid of parentheses
4v+4+12=0
We add all the numbers together, and all the variables
4v+16=0
We move all terms containing v to the left, all other terms to the right
4v=-16
v=-16/4
v=-4

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