12=-6y+3(y+5)

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Solution for 12=-6y+3(y+5) equation: 



12=-6y+3(y+5)

We move all terms to the left:

12-(-6y+3(y+5))=0



We calculate terms in parentheses: -(-6y+3(y+5)), so:

-6y+3(y+5)

We multiply parentheses

-6y+3y+15

We add all the numbers together, and all the variables

-3y+15

Back to the equation:

-(-3y+15)



We get rid of parentheses

3y-15+12=0

We add all the numbers together, and all the variables

3y-3=0

We move all terms containing y to the left, all other terms to the right

3y=3

y=3/3

y=1

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