12=-6y+3(y-6)

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Solution for 12=-6y+3(y-6) equation: 



12=-6y+3(y-6)

We move all terms to the left:

12-(-6y+3(y-6))=0



We calculate terms in parentheses: -(-6y+3(y-6)), so:

-6y+3(y-6)

We multiply parentheses

-6y+3y-18

We add all the numbers together, and all the variables

-3y-18

Back to the equation:

-(-3y-18)



We get rid of parentheses

3y+18+12=0

We add all the numbers together, and all the variables

3y+30=0

We move all terms containing y to the left, all other terms to the right

3y=-30

y=-30/3

y=-10

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