12=1/8(40x+16)

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Solution for 12=1/8(40x+16) equation: 



12=1/8(40x+16)

We move all terms to the left:

12-(1/8(40x+16))=0



Domain of the equation: 8(40x+16))!=0

x∈R



We multiply all the terms by the denominator


-(1+12*8(40x+16))=0



We calculate terms in parentheses: -(1+12*8(40x+16)), so:

1+12*8(40x+16)

determiningTheFunctionDomain
12*8(40x+16)+1

Wy multiply elements

96x(4+1

Back to the equation:

-(96x(4+1)



We add all the numbers together, and all the variables

-(96x5=0

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