12=1/8(40x+16)

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Solution for 12=1/8(40x+16) equation:



12=1/8(40x+16)
We move all terms to the left:
12-(1/8(40x+16))=0
Domain of the equation: 8(40x+16))!=0
x∈R
We multiply all the terms by the denominator
-(1+12*8(40x+16))=0
We calculate terms in parentheses: -(1+12*8(40x+16)), so:
1+12*8(40x+16)
determiningTheFunctionDomain 12*8(40x+16)+1
Wy multiply elements
96x(4+1
Back to the equation:
-(96x(4+1)
We add all the numbers together, and all the variables
-(96x5=0

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