12=10-(2/5)x

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Solution for 12=10-(2/5)x equation: 



12=10-(2/5)x

We move all terms to the left:

12-(10-(2/5)x)=0



Domain of the equation: 5)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(10-(+2/5)x)+12=0

We multiply all the terms by the denominator


-(10-(+2+12*5)x)=0



We calculate terms in parentheses: -(10-(+2+12*5)x), so:

10-(+2+12*5)x

determiningTheFunctionDomain
-(+2+12*5)x+10

We add all the numbers together, and all the variables

-62x+10

Back to the equation:

-(-62x+10)



We get rid of parentheses

62x-10=0

We move all terms containing x to the left, all other terms to the right

62x=10

x=10/62

x=5/31

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