12=13z-4z+6

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Solution for 12=13z-4z+6 equation: 



12=13z-4z+6

We move all terms to the left:

12-(13z-4z+6)=0

We add all the numbers together, and all the variables

-(9z+6)+12=0

We get rid of parentheses

-9z-6+12=0

We add all the numbers together, and all the variables

-9z+6=0

We move all terms containing z to the left, all other terms to the right

-9z=-6

z=-6/-9

z=2/3

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