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12=15b^2-6b
We move all terms to the left:
12-(15b^2-6b)=0
We get rid of parentheses
-15b^2+6b+12=0
a = -15; b = 6; c = +12;
Δ = b2-4ac
Δ = 62-4·(-15)·12
Δ = 756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{756}=\sqrt{36*21}=\sqrt{36}*\sqrt{21}=6\sqrt{21}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{21}}{2*-15}=\frac{-6-6\sqrt{21}}{-30} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{21}}{2*-15}=\frac{-6+6\sqrt{21}}{-30} $
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