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12=15x^2
We move all terms to the left:
12-(15x^2)=0
a = -15; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-15)·12
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*-15}=\frac{0-12\sqrt{5}}{-30} =-\frac{12\sqrt{5}}{-30} =-\frac{2\sqrt{5}}{-5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*-15}=\frac{0+12\sqrt{5}}{-30} =\frac{12\sqrt{5}}{-30} =\frac{2\sqrt{5}}{-5} $
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