12=2(-3z-3)

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Solution for 12=2(-3z-3) equation: 



12=2(-3z-3)

We move all terms to the left:

12-(2(-3z-3))=0



We calculate terms in parentheses: -(2(-3z-3)), so:

2(-3z-3)

We multiply parentheses

-6z-6

Back to the equation:

-(-6z-6)



We get rid of parentheses

6z+6+12=0

We add all the numbers together, and all the variables

6z+18=0

We move all terms containing z to the left, all other terms to the right

6z=-18

z=-18/6

z=-3

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