12=2(-9+3z)

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Solution for 12=2(-9+3z) equation: 



12=2(-9+3z)

We move all terms to the left:

12-(2(-9+3z))=0

We add all the numbers together, and all the variables

-(2(3z-9))+12=0



We calculate terms in parentheses: -(2(3z-9)), so:

2(3z-9)

We multiply parentheses

6z-18

Back to the equation:

-(6z-18)



We get rid of parentheses

-6z+18+12=0

We add all the numbers together, and all the variables

-6z+30=0

We move all terms containing z to the left, all other terms to the right

-6z=-30

z=-30/-6

z=+5

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