12=2(1+c)

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Solution for 12=2(1+c) equation: 



12=2(1+c)

We move all terms to the left:

12-(2(1+c))=0

We add all the numbers together, and all the variables

-(2(c+1))+12=0



We calculate terms in parentheses: -(2(c+1)), so:

2(c+1)

We multiply parentheses

2c+2

Back to the equation:

-(2c+2)



We get rid of parentheses

-2c-2+12=0

We add all the numbers together, and all the variables

-2c+10=0

We move all terms containing c to the left, all other terms to the right

-2c=-10

c=-10/-2

c=+5

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