12=2(u+4)-6u

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Solution for 12=2(u+4)-6u equation:



12=2(u+4)-6u
We move all terms to the left:
12-(2(u+4)-6u)=0
We calculate terms in parentheses: -(2(u+4)-6u), so:
2(u+4)-6u
We add all the numbers together, and all the variables
-6u+2(u+4)
We multiply parentheses
-6u+2u+8
We add all the numbers together, and all the variables
-4u+8
Back to the equation:
-(-4u+8)
We get rid of parentheses
4u-8+12=0
We add all the numbers together, and all the variables
4u+4=0
We move all terms containing u to the left, all other terms to the right
4u=-4
u=-4/4
u=-1

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