12=2(y+2)+2y

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Solution for 12=2(y+2)+2y equation: 



12=2(y+2)+2y

We move all terms to the left:

12-(2(y+2)+2y)=0



We calculate terms in parentheses: -(2(y+2)+2y), so:

2(y+2)+2y

We add all the numbers together, and all the variables

2y+2(y+2)

We multiply parentheses

2y+2y+4

We add all the numbers together, and all the variables

4y+4

Back to the equation:

-(4y+4)



We get rid of parentheses

-4y-4+12=0

We add all the numbers together, and all the variables

-4y+8=0

We move all terms containing y to the left, all other terms to the right

-4y=-8

y=-8/-4

y=+2

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