12=2(y+3)-8y

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Solution for 12=2(y+3)-8y equation: 



12=2(y+3)-8y

We move all terms to the left:

12-(2(y+3)-8y)=0



We calculate terms in parentheses: -(2(y+3)-8y), so:

2(y+3)-8y

We add all the numbers together, and all the variables

-8y+2(y+3)

We multiply parentheses

-8y+2y+6

We add all the numbers together, and all the variables

-6y+6

Back to the equation:

-(-6y+6)



We get rid of parentheses

6y-6+12=0

We add all the numbers together, and all the variables

6y+6=0

We move all terms containing y to the left, all other terms to the right

6y=-6

y=-6/6

y=-1

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