12=2+z(-6)

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Solution for 12=2+z(-6) equation: 



12=2+z(-6)

We move all terms to the left:

12-(2+z(-6))=0



We calculate terms in parentheses: -(2+z(-6)), so:

2+z(-6)

determiningTheFunctionDomain
z(-6)+2

We multiply parentheses

-6z+2

Back to the equation:

-(-6z+2)



We get rid of parentheses

6z-2+12=0

We add all the numbers together, and all the variables

6z+10=0

We move all terms containing z to the left, all other terms to the right

6z=-10

z=-10/6

z=-1+2/3

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