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12=2/3(w-20)
We move all terms to the left:
12-(2/3(w-20))=0
Domain of the equation: 3(w-20))!=0We multiply all the terms by the denominator
w∈R
-(2+12*3(w-20))=0
We calculate terms in parentheses: -(2+12*3(w-20)), so:
2+12*3(w-20)
determiningTheFunctionDomain 12*3(w-20)+2
Wy multiply elements
36w(w+2
Back to the equation:
-(36w(w+2)
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