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12=2/3)y
We move all terms to the left:
12-(2/3)y)=0
Domain of the equation: 3)y)+12!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-(+2/3)y)+12=0
We multiply all the terms by the denominator
-(+2=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
Równanie nie ma rozwiązania
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