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12=25+x-(19-2x)
We move all terms to the left:
12-(25+x-(19-2x))=0
We add all the numbers together, and all the variables
-(25+x-(-2x+19))+12=0
We calculate terms in parentheses: -(25+x-(-2x+19)), so:We get rid of parentheses
25+x-(-2x+19)
determiningTheFunctionDomain x-(-2x+19)+25
We get rid of parentheses
x+2x-19+25
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
-3x-6+12=0
We add all the numbers together, and all the variables
-3x+6=0
We move all terms containing x to the left, all other terms to the right
-3x=-6
x=-6/-3
x=+2
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