12=3(-2y-12)+12

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Solution for 12=3(-2y-12)+12 equation: 



12=3(-2y-12)+12

We move all terms to the left:

12-(3(-2y-12)+12)=0



We calculate terms in parentheses: -(3(-2y-12)+12), so:

3(-2y-12)+12

We multiply parentheses

-6y-36+12

We add all the numbers together, and all the variables

-6y-24

Back to the equation:

-(-6y-24)



We get rid of parentheses

6y+24+12=0

We add all the numbers together, and all the variables

6y+36=0

We move all terms containing y to the left, all other terms to the right

6y=-36

y=-36/6

y=-6

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