12=3(b+12)

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Solution for 12=3(b+12) equation:



12=3(b+12)
We move all terms to the left:
12-(3(b+12))=0
We calculate terms in parentheses: -(3(b+12)), so:
3(b+12)
We multiply parentheses
3b+36
Back to the equation:
-(3b+36)
We get rid of parentheses
-3b-36+12=0
We add all the numbers together, and all the variables
-3b-24=0
We move all terms containing b to the left, all other terms to the right
-3b=24
b=24/-3
b=-8

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