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12=3(x-5)+6x
We move all terms to the left:
12-(3(x-5)+6x)=0
We calculate terms in parentheses: -(3(x-5)+6x), so:We get rid of parentheses
3(x-5)+6x
We add all the numbers together, and all the variables
6x+3(x-5)
We multiply parentheses
6x+3x-15
We add all the numbers together, and all the variables
9x-15
Back to the equation:
-(9x-15)
-9x+15+12=0
We add all the numbers together, and all the variables
-9x+27=0
We move all terms containing x to the left, all other terms to the right
-9x=-27
x=-27/-9
x=+3
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