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12=3/5b
We move all terms to the left:
12-(3/5b)=0
Domain of the equation: 5b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
-(+3/5b)+12=0
We get rid of parentheses
-3/5b+12=0
We multiply all the terms by the denominator
12*5b-3=0
Wy multiply elements
60b-3=0
We move all terms containing b to the left, all other terms to the right
60b=3
b=3/60
b=1/20
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