12=3/8(z-5)

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Solution for 12=3/8(z-5) equation: 



12=3/8(z-5)

We move all terms to the left:

12-(3/8(z-5))=0



Domain of the equation: 8(z-5))!=0

z∈R



We multiply all the terms by the denominator


-(3+12*8(z-5))=0



We calculate terms in parentheses: -(3+12*8(z-5)), so:

3+12*8(z-5)

determiningTheFunctionDomain
12*8(z-5)+3

Wy multiply elements

96z(z+3

Back to the equation:

-(96z(z+3)





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96z(z+3





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