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12=3/z
We move all terms to the left:
12-(3/z)=0
Domain of the equation: z)!=0We add all the numbers together, and all the variables
z!=0/1
z!=0
z∈R
-(+3/z)+12=0
We get rid of parentheses
-3/z+12=0
We multiply all the terms by the denominator
12*z-3=0
We add all the numbers together, and all the variables
12z-3=0
We move all terms containing z to the left, all other terms to the right
12z=3
z=3/12
z=1/4
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