12=3y-y+4y=

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Solution for 12=3y-y+4y= equation: 



12=3y-y+4y=

We move all terms to the left:

12-(3y-y+4y)=0

We add all the numbers together, and all the variables

-(+6y)+12=0

We get rid of parentheses

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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