12=4(b+20)-12

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Solution for 12=4(b+20)-12 equation:



12=4(b+20)-12
We move all terms to the left:
12-(4(b+20)-12)=0
We calculate terms in parentheses: -(4(b+20)-12), so:
4(b+20)-12
We multiply parentheses
4b+80-12
We add all the numbers together, and all the variables
4b+68
Back to the equation:
-(4b+68)
We get rid of parentheses
-4b-68+12=0
We add all the numbers together, and all the variables
-4b-56=0
We move all terms containing b to the left, all other terms to the right
-4b=56
b=56/-4
b=-14

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