12=4(k+1)

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Solution for 12=4(k+1) equation: 



12=4(k+1)

We move all terms to the left:

12-(4(k+1))=0



We calculate terms in parentheses: -(4(k+1)), so:

4(k+1)

We multiply parentheses

4k+4

Back to the equation:

-(4k+4)



We get rid of parentheses

-4k-4+12=0

We add all the numbers together, and all the variables

-4k+8=0

We move all terms containing k to the left, all other terms to the right

-4k=-8

k=-8/-4

k=+2

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