12=5(-3a+2)-(a-1)

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Solution for 12=5(-3a+2)-(a-1) equation: 



12=5(-3a+2)-(a-1)

We move all terms to the left:

12-(5(-3a+2)-(a-1))=0



We calculate terms in parentheses: -(5(-3a+2)-(a-1)), so:

5(-3a+2)-(a-1)

We multiply parentheses

-15a-(a-1)+10

We get rid of parentheses

-15a-a+1+10

We add all the numbers together, and all the variables

-16a+11

Back to the equation:

-(-16a+11)



We get rid of parentheses

16a-11+12=0

We add all the numbers together, and all the variables

16a+1=0

We move all terms containing a to the left, all other terms to the right

16a=-1

a=-1/16

a=-1/16

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