12=6(z-2)=5z

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Solution for 12=6(z-2)=5z equation: 



12=6(z-2)=5z

We move all terms to the left:

12-(6(z-2))=0



We calculate terms in parentheses: -(6(z-2)), so:

6(z-2)

We multiply parentheses

6z-12

Back to the equation:

-(6z-12)



We get rid of parentheses

-6z+12+12=0

We add all the numbers together, and all the variables

-6z+24=0

We move all terms containing z to the left, all other terms to the right

-6z=-24

z=-24/-6

z=+4

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