12=6c-(5c-10)

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Solution for 12=6c-(5c-10) equation: 



12=6c-(5c-10)

We move all terms to the left:

12-(6c-(5c-10))=0



We calculate terms in parentheses: -(6c-(5c-10)), so:

6c-(5c-10)

We get rid of parentheses

6c-5c+10

We add all the numbers together, and all the variables

c+10

Back to the equation:

-(c+10)



We get rid of parentheses

-c-10+12=0

We add all the numbers together, and all the variables

-1c+2=0

We move all terms containing c to the left, all other terms to the right

-c=-2

c=-2/-1

c=+2

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