If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12=6x^2
We move all terms to the left:
12-(6x^2)=0
a = -6; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-6)·12
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{2}}{2*-6}=\frac{0-12\sqrt{2}}{-12} =-\frac{12\sqrt{2}}{-12} =-\frac{\sqrt{2}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{2}}{2*-6}=\frac{0+12\sqrt{2}}{-12} =\frac{12\sqrt{2}}{-12} =\frac{\sqrt{2}}{-1} $
| 8x+12-3=23 | | 85-3x=5 | | 4+2x+3x=7+6x | | 8/7y=168/9 | | 70*(x+200)=20x*7 | | 9-2(7x-5=3(x-5) | | x^2−2x=22 | | 17/13=10/v | | 4(3y+1)-12(y+1)=0 | | 17/13=10/w | | x^2=-2.17 | | 1+3v=6+4v | | (u+2)^(2)-12=0 | | 23x^2-123x+40=0 | | (-3)m=4.2 | | 25x-6=6 | | 19=-2(3p+1)-p | | u/4=17/7 | | 40+6(h-6)=-20 | | 5r-6r=5+3r-3r | | .75x-5/2=4 | | 6x-2x-8=3x+1x+6-14 | | 2(x−5)=10 | | 3/4x-5/2=4 | | 4(x+2)-4=12 | | 4(3t+1)-12t+1)=0 | | 8(8−k)=−72k | | 23x^2-170x+63=0 | | -t/4=5/2 | | −2(y−3)=y+24 | | 7k+5(3-2k)=24 | | 2x=20x+10 |