12=7(y-4)-3y

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Solution for 12=7(y-4)-3y equation: 



12=7(y-4)-3y

We move all terms to the left:

12-(7(y-4)-3y)=0



We calculate terms in parentheses: -(7(y-4)-3y), so:

7(y-4)-3y

We add all the numbers together, and all the variables

-3y+7(y-4)

We multiply parentheses

-3y+7y-28

We add all the numbers together, and all the variables

4y-28

Back to the equation:

-(4y-28)



We get rid of parentheses

-4y+28+12=0

We add all the numbers together, and all the variables

-4y+40=0

We move all terms containing y to the left, all other terms to the right

-4y=-40

y=-40/-4

y=+10

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