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12=72/(3+2x)
We move all terms to the left:
12-(72/(3+2x))=0
Domain of the equation: (3+2x))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x)!=-3
x!=-3/1
x!=-3
x∈R
-(72/(2x+3))+12=0
We multiply all the terms by the denominator
-(72+12*(2x+3))=0
We calculate terms in parentheses: -(72+12*(2x+3)), so:We get rid of parentheses
72+12*(2x+3)
determiningTheFunctionDomain 12*(2x+3)+72
We multiply parentheses
24x+36+72
We add all the numbers together, and all the variables
24x+108
Back to the equation:
-(24x+108)
-24x-108=0
We move all terms containing x to the left, all other terms to the right
-24x=108
x=108/-24
x=-4+1/2
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