12=7x+10/8x+6.

Solution for 12=7x+10/8x+6. equation:

12=7x+10/8x+6.

We move all terms to the left:

12-(7x+10/8x+6.)=0


Domain of the equation: 8x+6.)!=0

x∈R


We add all the numbers together, and all the variables

-(7x+10/8x+6)+12=0

We get rid of parentheses

-7x-10/8x-6+12=0

We multiply all the terms by the denominator


-7x*8x-6*8x+12*8x-10=0

Wy multiply elements

-56x^2-48x+96x-10=0

We add all the numbers together, and all the variables

-56x^2+48x-10=0

a = -56; b = 48; c = -10;
Δ = b2-4ac
Δ = 482-4·(-56)·(-10)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-8}{2*-56}=\frac{-56}{-112}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+8}{2*-56}=\frac{-40}{-112}
=5/14
$