12=8(y-6)+4y

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Solution for 12=8(y-6)+4y equation: 



12=8(y-6)+4y

We move all terms to the left:

12-(8(y-6)+4y)=0



We calculate terms in parentheses: -(8(y-6)+4y), so:

8(y-6)+4y

We add all the numbers together, and all the variables

4y+8(y-6)

We multiply parentheses

4y+8y-48

We add all the numbers together, and all the variables

12y-48

Back to the equation:

-(12y-48)



We get rid of parentheses

-12y+48+12=0

We add all the numbers together, and all the variables

-12y+60=0

We move all terms containing y to the left, all other terms to the right

-12y=-60

y=-60/-12

y=+5

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