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12=8-2(x+3)
We move all terms to the left:
12-(8-2(x+3))=0
We calculate terms in parentheses: -(8-2(x+3)), so:We get rid of parentheses
8-2(x+3)
determiningTheFunctionDomain -2(x+3)+8
We multiply parentheses
-2x-6+8
We add all the numbers together, and all the variables
-2x+2
Back to the equation:
-(-2x+2)
2x-2+12=0
We add all the numbers together, and all the variables
2x+10=0
We move all terms containing x to the left, all other terms to the right
2x=-10
x=-10/2
x=-5
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