12=m2/3+-8

Solution for 12=m2/3+-8 equation:

12=m2/3+-8

We move all terms to the left:

12-(m2/3+-8)=0

We add all the numbers together, and all the variables

-(m2/3-8)+12=0

We get rid of parentheses

-m2/3+8+12=0

We multiply all the terms by the denominator


-m2+8*3+12*3=0

We add all the numbers together, and all the variables

-1m^2+60=0

a = -1; b = 0; c = +60;
Δ = b2-4ac
Δ = 02-4·(-1)·60
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*-1}=\frac{0-4\sqrt{15}}{-2}
=-\frac{4\sqrt{15}}{-2}
=-\frac{2\sqrt{15}}{-1}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*-1}=\frac{0+4\sqrt{15}}{-2}
=\frac{4\sqrt{15}}{-2}
=\frac{2\sqrt{15}}{-1}
$