12=z-28

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Solution for 12=z-28 equation: 



12=z-28

We move all terms to the left:

12-(z-28)=0

We get rid of parentheses

-z+28+12=0

We add all the numbers together, and all the variables

-1z+40=0

We move all terms containing z to the left, all other terms to the right

-z=-40

z=-40/-1

z=+40

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