12X*40x=4922

Solution for 12X*40x=4922 equation:

12X*40X=4922

We move all terms to the left:

12X*40X-(4922)=0

Wy multiply elements

480X^2-4922=0

a = 480; b = 0; c = -4922;
Δ = b2-4ac
Δ = 02-4·480·(-4922)
Δ = 9450240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9450240}=\sqrt{256*36915}=\sqrt{256}*\sqrt{36915}=16\sqrt{36915}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{36915}}{2*480}=\frac{0-16\sqrt{36915}}{960}
=-\frac{16\sqrt{36915}}{960}
=-\frac{\sqrt{36915}}{60}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{36915}}{2*480}=\frac{0+16\sqrt{36915}}{960}
=\frac{16\sqrt{36915}}{960}
=\frac{\sqrt{36915}}{60}
$