12a+(10a-4)+2(6a+8)=102

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Solution for 12a+(10a-4)+2(6a+8)=102 equation: 



12a+(10a-4)+2(6a+8)=102

We move all terms to the left:

12a+(10a-4)+2(6a+8)-(102)=0

We multiply parentheses

12a+(10a-4)+12a+16-102=0

We get rid of parentheses

12a+10a+12a-4+16-102=0

We add all the numbers together, and all the variables

34a-90=0

We move all terms containing a to the left, all other terms to the right

34a=90

a=90/34

a=2+11/17

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