12a+(10a-4)+2(6a+8)=102

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Solution for 12a+(10a-4)+2(6a+8)=102 equation:



12a+(10a-4)+2(6a+8)=102
We move all terms to the left:
12a+(10a-4)+2(6a+8)-(102)=0
We multiply parentheses
12a+(10a-4)+12a+16-102=0
We get rid of parentheses
12a+10a+12a-4+16-102=0
We add all the numbers together, and all the variables
34a-90=0
We move all terms containing a to the left, all other terms to the right
34a=90
a=90/34
a=2+11/17

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