12a+22b=(3*(9a-4b))/2

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Solution for 12a+22b=(3*(9a-4b))/2 equation: 


x in (-oo:+oo)

12*a+22*b = (3*(9*a-(4*b)))/2 // - (3*(9*a-(4*b)))/2

12*a-((3*(9*a-(4*b)))/2)+22*b = 0

(-3/2)*(9*a-4*b)+12*a+22*b = 0

12*a-3/2*(9*a-4*b)+22*b = 0

12*a-3/2*(9*a-4*b)+22*b = 0

6*b-3/2*a+22*b = 0

28*b-3/2*a = 0

28*b-3/2*a = 0

x belongs to the empty set

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